interp3 function returns NaN

Question

Matt Badaye 2013-12-31

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/111072-interp3-function-returns-nan

回答： Walter Roberson 2013-12-31

I have a parameter called Cm that I need to interpolate in 3D between the points defined by the following specific coordinates:

x=[4 5 6];
y=[0.55 0.7];
z=[40 80];

the values of the Cm at these specific points are as follows:

            Cm(1,1,1)= 2.5;
            Cm(2,1,1)=3;
            Cm(3,1,1)=4;
            Cm(1,2,1)= 2.8;
            Cm(2,2,1)=3.5;
            Cm(3,2,1)=4.5;
            Cm(1,1,2)= 1.5;
            Cm(2,1,2)=1.8;
            Cm(3,1,2)=2;
            Cm(1,2,2)= 1.8;
            Cm(2,2,2)=2.2;
            Cm(3,2,2)=2.8;

when I use iterp3 as shown below:

interp3(Cm,0.65,4.5,50)

it returns NaN. the Xq, Yq, Zq are all inside the x,y, and z intervals. could you let me know why is this not working?

thanks

Matt

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2013-12-31

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/111072-interp3-function-returns-nan#answer_119724

在 MATLAB Online 中打开

Vq = interp3(V,Xq,Yq,Zq) assumes a default grid of sample points. The default grid points cover the region, X=1:n, Y=1:m, Z=1:p, where [m,n,p] = size(V).

Notice the "default grid". 0.65 is less than 1 and so must be outside the default grid.