how to unzip files using external unzip software?

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sandy
sandy 2014-1-9
评论： Arjun Ajit Kottara 2022-5-6
i have 50000 zip files.i need to unzip all those files and want to fetch .txt files alone from each zip files...any help..

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Friedrich
Friedrich 2014-1-9
编辑：Friedrich 2014-1-9
Hi,
I would use JAVA to get what you want, e.g. the following example extract the .txt files in a zip files only (done with R2013b):
zipFile = org.apache.tools.zip.ZipFile('Untitled1.zip');
entries = zipFile.getEntries;
while entries.hasMoreElements
entry = entries.nextElement;
entryName = char(entry.getName);
[~,~,ext] = fileparts(entryName);
if strcmp(ext,'.txt')
inputStream = zipFile.getInputStream(entry);
fileOutputStream = java.io.FileOutputStream(fullfile(pwd,entryName));
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
fileOutputStream.close;
inputStream.close;
end
end
zipFile.close
UPDATED VERSION FOR SCANNING A FOLDER FOR ZIP FILES AND PROCESS ALL OF THEM
zipfolder = 'C:\Users\fhempel\Desktop\tmp';
extractionfolder = 'C:\Users\fhempel\Desktop\tmp';
zipfiles = dir([zipfolder,'\*.zip']);
for i=1:numel(zipfiles)
zipFile = org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
entries = zipFile.getEntries;
while entries.hasMoreElements
entry = entries.nextElement;
entryName = char(entry.getName);
[~,~,ext] = fileparts(entryName);
if strcmp(ext,'.txt')
inputStream = zipFile.getInputStream(entry);
if ~exist(fullfile(extractionfolder,zipfiles(i).name(1:end-4)),'dir')
mkdir(fullfile(extractionfolder,zipfiles(i).name(1:end-4)))
end
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,zipfiles(i).name(1:end-4),entryName));
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
fileOutputStream.close;
inputStream.close;
end
end
zipFile.close
end
  8 个评论
显示 6更早的评论
Friedrich
Friedrich 2014-1-9
I dont know the zipsearch functon and I dont know what it returns. But you need to adjust this line
zipFile = org.apache.tools.zip.ZipFile(fullfile(zipfolder,zipfiles(i).name));
Basically the argument needs to be the absolut path to the zip file you like to process, e.g. C:\some_folder\myzip.zip.
Since the output should be in one folder you can remove this three lines:
if ~exist(fullfile(extractionfolder,zipfiles(i).name(1:end-4)),'dir')
mkdir(fullfile(extractionfolder,zipfiles(i).name(1:end-4)))
end
Finally this one needs to be adjusted:
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,zipfiles(i).name(1:end-4),entryName));
I guess it should be:
fileOutputStream = java.io.FileOutputStream(fullfile(extractionfolder,entryName));
Please also update the extractionfolder variable to an existing folder on your machine. In addition please also update the zipfolder variable accordingly.
Arjun Ajit Kottara
Arjun Ajit Kottara 2022-5-6
Hey, I was searching for this answer!, but I need to just extract the multiple zip files to another targer folder, so what changes should I make? since this will filter out non .txt files..

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更多回答（2 个）

Walter Roberson
Walter Roberson 2014-1-9
  1 个评论
sandy
sandy 2014-1-9
编辑：sandy 2014-1-9
thanks...this s for fetching files in a dir or a specific folder..fetching inside each zip file is difficult here.any ideas..also.matlab unzip() function is faster than external program zip.exe ?..suggestion

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Peng Zheng
Peng Zheng 2014-10-14
Hello, I think this answer is very useful for me.But I don't understand this two lines:
streamCopier = com.mathworks.mlwidgets.io.InterruptibleStreamCopier.getInterruptibleStreamCopier;
streamCopier.copyStream(inputStream, fileOutputStream);
Can you please be so kind to tell me what does this mean and what it will return?

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