how to plot many plots at the same one?

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mika
mika 2014-1-13
回答： Bruno Pop-Stefanov 2014-1-15
Hello,
I'm tying to show the result (five plots for detected patterns) of the code below in one plot but in vain,
any idea please
help is much appreciated
n = 50 ;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
figure(pId) ; clf ; hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
set( gcf, 'Units', 'normalized' ) ;
set( gcf, 'Position', [0 0 0.4 0.7] ) ;
end

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采纳的回答

Image Analyst
Image Analyst 2014-1-13
编辑：Image Analyst 2014-1-13
Try using subplot() and getting rid of the set()s:
n = 50;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
subplot(2,3,pId); % Put plot into this location.
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
% figure(pId) ; clf ;
hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
% set( gca, 'Units', 'normalized' ) ;
% set( gca, 'Position', [0 0 0.4 0.7] ) ;
end
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
  2 个评论
mika
mika 2014-1-15
Thank you for your fast reply,
i'm trying to show the result of the shape recognition of 5 patterns at the same plot wich is only one plot. not the five plot at one using subplot.
any idea
thank you
Image Analyst
Image Analyst 2014-1-15
Try this:
n = 50;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
% Append these r and c to the master list.
if pId == 1
% First one
allR = r;
allC = c;
else
allR = [allR; r(:)];
allC = [allC; c(:)];
end
end
plot(allC, allR, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);

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更多回答（1 个）

Bruno Pop-Stefanov
Bruno Pop-Stefanov 2014-1-15
Hi Mika,
If you want to draw all the patterns in the same figure, you should indeed use hold on, however, by calling figure with a different ID number at each iteration of the loop, you create a new figure for each pattern. Also, you use clf which clears everything that was previously plotted on the current figure. Change your code to the following and that should work:
close all
clear all
clc
n = 50 ;
A = double( rand(n, n+1) > 0.5 ) ;
B = 2*A - 1 ;
patterns = {[1 0 1; 0 1 0; 1 0 1]; ... % X
[1 0 1; 0 1 0; 1 0 0]; ... % Y
[0 1 0; 1 0 1; 0 1 0]; ... % O
[0 0 0; 1 1 1; 0 0 0]; ... % -
[1 0 0; 1 0 0; 1 1 1]} ; % L
labels = {'X', 'Y', 'O', '-', 'L'} ;
matches = cell( size(labels )) ;
for pId = 1 : numel( patterns )
nel = numel( patterns{pId} ) ;
ker = 2*patterns{pId} - 1 ;
[r, c] = find( conv2(B, rot90(rot90(ker)), 'same') == nel ) ;
matches{pId} = [r, c] ;
figure(1) ; hold on ;
spy(A) ;
plot( c, r, 'r+', 'MarkerSize', 20 ) ;
title( sprintf( 'Matches for "%s" pattern', labels{pId} )) ;
set( gcf, 'Units', 'normalized' ) ;
set( gcf, 'Position', [0 0 0.4 0.7] ) ;
end

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