I need my angles in the [-pi:pi] range instead of [0:2*pi]?
21 次查看(过去 30 天)
显示 更早的评论
I have an angle in degrees, 225 degrees. Now degtorad(225) function gives me:
>>degtorad(225)
ans =
3.9270 radians
above 'ans' is in the range 0:2pi
I want to know the procedure that i get an answer in the range -pi:pi, as 225 degrees is also equal to -2.3562 radians
225 degree=3.9270 rad
225 degree=-2.3562 rad.
I hope I have made my point clear.
Thank you in advance.
2 个评论
Walter Roberson
2021-7-28
Good point, @krishna teja, wrapToPi should work well... at least for people who have the Mapping Toolbox.
采纳的回答
Walter Roberson
2014-1-13
R(R > pi) = R(R > pi) - 2*pi;
3 个评论
Jacob Ward
2017-9-6
True, but putting it inside a while loop would take care of the multiple turns, yes?
temp = 0;
while R != temp
temp = R;
R(R > pi) = R(R > pi) - 2*pi;
end
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!