can you help me to ploting the number of operations and time of execution
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function pgdA
n=1000;
i=45;
while mod(n, i)~=0;
i=i-1;
end
flops mod(n,i);
plot mod(n,i);
3 个评论
Mihir Daptardar
2014-1-21
Can you elaborate what 'flops' is? Is it a custom function that you have written?
Walter Roberson
2014-1-21
"flops" is "floating point operations per second". There was a time when it had meaning in computers, but it does not have much meaning now.
Walter Roberson
2014-1-21
As I have indicated in multiple posts, "flops", floating point operations per second, is not meaningful in modern computers, and there is no way to calculate it now.
If, though, you wanted to count "actions" like you did in http://www.mathworks.co.uk/matlabcentral/answers/105512-plotting-the-number-of-actions-for-ex-i-i-1-action-pgd-n-i-action-pgd-n-action then we might be able to help you, provided that you indicate all the different "actions" that you want to be counted individually.
Please note that your code has nothing to do with finding "mod", and is instead an algorithm for finding the greatest divisor of "n" that is at most "i"; with those particular values it would be 25 that would be left for "i"
回答（1 个）
Paul
2014-1-21
Do you mean something like this:
n=10000;
i=47;
j=0;
while mod(n, i)~=0;
if(j==0)
tic
end
i=i-1;
j=j+1;
t(j)=toc;
tic
end
j=1:j;
plot(j,t),xlabel('iteration number'),ylabel('time [s]');
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2021-8-20
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