Why I can not do this surf?

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Ayob
Ayob 2014-1-19
编辑： Image Analyst 2014-1-19
I have made three matrices X,Y and Z. All of them are 144*1 matrices. I use surf(X,Y,Z), but it doesn't work!
[EDIT] Ayob "Answered" his own question with this, but I moved it up here since it's not an answer:
I have X, Y and Z matrices. How can I change X, Y and Z to the forms that enable me use surf? I have all nodes but in (x,y,z) shape.
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Paul
Paul 2014-1-19
need more info on how those vectors look like. is it like
x= [1 2 3 4 1 2 3 4 1 2 3 4]'
If the nodes are not equally distributed you'll still need to interpolate like in my other comment.

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回答（2 个）

Paul
Paul 2014-1-19
Because Z should be a 144*144 matrix. 1 value for each pair of x and y values.
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Ayob
Ayob 2014-1-19
编辑：Ayob 2014-1-19
This is not exactly what I want. What other function should I use?(I have my vales in x,y,z which are in (X,Y,Z).
Paul
Paul 2014-1-19
Sounds like you have scattered data, need more info on that. You can probably interpolate the data using griddata to a desired grid like this:
[xq,yq] = meshgrid(-2:.2:2, -2:.2:2);
zq = griddata(x,y,z,xq,yq);
surf(xq,yq,zq)
Where xq and yq are the desired interpolation points.

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Image Analyst
Image Analyst 2014-1-19
If you have only a few scattered points here and there, and these are listed in your x,y,z array, then you need to use the griddedInterpolant class. It will estimate z values for the missing coordinate locations and build a complete surface.
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Image Analyst
Image Analyst 2014-1-19
编辑：Image Analyst 2014-1-19
If you have older versions of MATLAB, use griddata() or TriScatteredInterp(). These are deprecated (not recommended, and scheduled to be eliminated) and the new recommendation is to use griddedInterpolant.

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