How to plot an equation with two independent and one dependent variable?
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p= 0.5 * ∑ ( (-1)^i * (w!/(i!*(w-i)!))*(1-(2*f*i)/w)^k-1)
where ∑ is between i=0 to w, f= w^2/(4*l), l=any prime number greater than 53, k varies between 1 to 100, w varies between 5 to 40.
i want to plot a graph 'k vs p' with w=fixed value eg.w=9
l=53 w=9 f= w^2/(4*l); for k=1:100 for i=0:w temp1=(-1)^i*nchoosek(w,i)*(1-(1-(2*f*i)/w)^k-1); temp(1,i+1)=temp1; end; temp2=0.5 * sum(temp); temp3(1,k)=temp2; end; plot(k,temp3);
though this code is not showing error the plot generated is wrong. the p values must be in the order of 10^-4 to 10^-12 for k ranging from 1 to 100.
采纳的回答
Amit
2014-1-19
There is one difference between the equation and your code (however that does not fixes the issue though).
l=53;
w=30;
f= w^2/(4*l);
temp3 = zeros(1,100);
for k=1:100
temp = 0;
for i=0:w
temp1=((-1)^i)*(nchoosek(w,i))*((1-(2*f*i)/w)^k-1); % This line was different from the equation
temp= temp + temp1;
end;
temp3(1,k)=0.5 * temp;
end;
plot(1:100,temp3);
For small values of K, the order comes down to what you mentioned. Are you sure about the equation? or the values of K in which this order appear is 10 instead of 100?
更多回答（1 个）
Paul
2014-1-19
0 个投票
it plots only points in vertical line because when you plot k has only a single value, namely 100. Add k=1:100; before the plot command, then it should plot what you want.
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