Reduction of code lines

2 次查看(过去 30 天)
Alright, so I've written this particular thing to blur an image and I've been wondering if I could reduce the number of lines or perhaps cut down the redundancies within this code especially the last line which copies one matrix to an other. Any over the top ideas would also be appreciated!
a=512;
b = a^2/16;
c=(sqrt(b)-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
F1 = zeros(width);
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e)=F1(e,e);

采纳的回答

Walter Roberson
Walter Roberson 2014-1-21
编辑:Walter Roberson 2014-1-21
a = 512;
B = a/4;
c = (B-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e) = 0;

更多回答(1 个)

Amit
Amit 2014-1-21
Its a good code. The only place I think there is a chance is
a=512;
b = a^2/16;
c=(sqrt(b)-1)/2;
ft11 = fftshift(fft2(myImage));
width = size(myImage,1);
%F1 = zeros(width); % You dont need to store these zeros
d = width/2;
e = (d-c:d+c)+1;
ft11(e,e)=zeros(e);
  1 个评论
Amit
Amit 2014-1-21
编辑:Amit 2014-1-21
you might think of putting (d-c:d+c)+1 directly. However this might create more overhead, due to temporary storing those values (3 times). (I might be wrong about this)

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by