Reduction of code lines

Question

Ayesha 2014-1-21

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113060-reduction-of-code-lines

编辑： Walter Roberson 2014-1-21

Alright, so I've written this particular thing to blur an image and I've been wondering if I could reduce the number of lines or perhaps cut down the redundancies within this code especially the last line which copies one matrix to an other. Any over the top ideas would also be appreciated!

a=512;
b = a^2/16; 
c=(sqrt(b)-1)/2;  
ft11 = fftshift(fft2(myImage)); 
width = size(myImage,1); 
F1 = zeros(width);  
d = width/2; 
e = (d-c:d+c)+1;
ft11(e,e)=F1(e,e);

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Answer 1

Walter Roberson 2014-1-21

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https://ww2.mathworks.cn/matlabcentral/answers/113060-reduction-of-code-lines#answer_121577

编辑：Walter Roberson 2014-1-21

在 MATLAB Online 中打开

a = 512;
B = a/4; 
c = (B-1)/2;  
ft11 = fftshift(fft2(myImage)); 
width = size(myImage,1);
d = width/2; 
e = (d-c:d+c)+1;
ft11(e,e) = 0;

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Answer 2

Amit 2014-1-21

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113060-reduction-of-code-lines#answer_121573

在 MATLAB Online 中打开

Its a good code. The only place I think there is a chance is

a=512;
b = a^2/16; 
c=(sqrt(b)-1)/2;  
ft11 = fftshift(fft2(myImage)); 
width = size(myImage,1); 
%F1 = zeros(width);  % You dont need to store these zeros
d = width/2; 
e = (d-c:d+c)+1;
ft11(e,e)=zeros(e);

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Amit 2014-1-21

编辑：Amit 2014-1-21

you might think of putting (d-c:d+c)+1 directly. However this might create more overhead, due to temporary storing those values (3 times). (I might be wrong about this)

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