can i get rid of rectangular coordinates and get something like a blade shape image in matlab as shown in figure. If yes then please refer me to some example

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Rizwana
Rizwana 2014-1-21
回答： Image Analyst 2014-1-27

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Bjorn Gustavsson
Bjorn Gustavsson 2014-1-21
yes. Use:
surf(X,Y,Z,C),shading flat.view(0,90)
Where you might set the Z-matrix to all zeros (or something else if you'd rather like that)
HTH
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Rizwana
Rizwana 2014-1-22
Sir: It is giving error saying dimensions of the matrix are not matching right after the 1st line i tried. XYZ = [R.*cos(ca),R.*sin(ca),cptot];
Bjorn Gustavsson
Bjorn Gustavsson 2014-1-22
You have to check that their sizes are the same, first check:
whos R ca cptot
then hopefully you'll only have to transpose R:
XYZ = [R.'.*cos(ca),R.'.*sin(ca),cptot];
HTH

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Walter Roberson
Walter Roberson 2014-1-27
Have a look at "Obtaining Angular Directions in a Projection Space" in the document http://www.mathworks.com/help/map/accessing-computing-and-inverting-map-projection-data.html#f11-12738 . The graph shown there in 6. -- isn't that the same kind of graph that you need, except with a greater mapping angle? If so then you can use the setup shown in 1. but with different lat and lon limits.
Image Analyst
Image Analyst 2014-1-27
If it's just a rubber sheet stretch, then imtransform() can do that.

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