Hold True Value for finite length of time
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I am fairly new to matlab and have been getting to grips with it over the past month so excuse me if I missed something very obvious.
I am using a relational operator that will output a true value (1) when the input single goes beyond a certain range. What I require is that when the input single goes beyond this certain range and the output single becomes true, to hold this true value (e.g. the constant one) for a period of time e.g. 10 seconds.
I have been trying to use enabled subsystems, switches and zero hold blocks but with little success.
Any help would be much appreciated.
Modeling using Simulink
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Doug Eastman
2011-7-11
The easiest solution is using Stateflow: create two states off and on, transition from off to on when the signal is tripped, then return to off using 'after(10,sec)'.
In Simulink it's a little more complicated, but basically you can have an enabled subsystem with a constant one going into an integrator going into a compare to constant block set to less than or equal to -1. That will stay on for 10 seconds once the enable port is on. Then the trick is to latch the enable signal so it will stay on as long as necessary. You can use a relay block for that, but you'll need to feed the output of the enabled subsystem back and add it to the initial signal in order to reset the relay after 10 seconds have passed.
Or use a MATLAB Function block set to a discrete sample time of 0.1 with the following code:
function y = fcn(u)
%#codegen
persistent tick started
if isempty(tick)
tick = 0;
started = 0;
end
y=0;
if u == 1
started = 1;
end
if started
if tick<100
tick=tick+1;
y = 1;
else
tick = 0;
started = 0;
end
end
3 个评论
Dan Willans
2015-2-11
Hi there,
Are you able to put up an image of how you got this to work? I'm trying to get my simulink model to hold a constant 1 for 20 seconds once a timer has reached the value 10.
I can't seem to work it out!
Thank you!
Dan
Peter Ma
2018-9-27
编辑:Peter Ma
2018-9-27
I totally agree with what Doug Eastman said.
By using his second method, I have made a block that can convert 'the length of time (s)' to 'pulse' with corresponding time.
inside subsystem:
The output looks like:
Be careful that the initial value of 'Sample and Hold' block should be a very small value, rather than zero. Otherwise, there will be an error for the 'Divide' block. (1 divided by 0 is infinity)
更多回答(3 个)
Kaustubha Govind
2011-7-11
An important thing to keep in mind when modeling in Simulink is that blocks run according to their sample time (see this blog post for information how you can look at your block's sample time). So if you are using a zero-order hold block, it will only hold the input for one sample period - you need to sample the sample time of the zero-order hold block to 10 seconds to achieve what you need.
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Kaustubha Govind
2011-7-11
Owen: It's not clear if you're saying whether this answer resolves your question or not. If it does, please accept it. If not, please elaborate on how it is not sufficient.
Jie
2017-1-18
Hi, I think I solved the problem in simulink. Please see the picture below. The 'Discrete-Time Integrator' Gain value should set to 1.
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Vijay
2018-8-1
I want to hold the newest peak (the last peak – input changing from 0 to 1) for an hour. I used the zero order hold Block for that purpose (sample time 3600s). But the problem with zero order hold block is, it sometimes omits the peak and I am not getting why it does that.
As you see in the attached picture, the blue line is the held curve and the red one is the input. One can see that, in the places where I marked wrong, the peak is not held as wanted it to.
Anybody has experience with this matter?
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