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repeating an index number n times in a vector

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Siem Nijskens
Siem Nijskens 2014-1-23
评论： Siem Nijskens 2014-1-23
Hi People,
I'd like to transform a vector p like this one. p=[3 0 2 2 1 0 3]
Into a new vector that has n times the indexnumber of n, for example:
new vector: v=[1 1 1 3 3 4 4 5 7 7 7] so it has 3 times 1, zero times 2, 2 times 3 and so on.
the numbers generated in p are variable but are always between 0 and 15
I hope you can help me.
Regards, Siem

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采纳的回答

Amit
Amit 2014-1-23
v = [];
count = 1;
for j = 1:length(p)
if p(j) ~= 0
v(count:count+p(j)-1) = j*ones(p(j),1);
count = count + p(j);
end
end
  1 个评论
Siem Nijskens
Siem Nijskens 2014-1-23
Hi Amit,
Thank you so much this has been driving me crazy but your solution works perfectly.
Regards, Siem

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更多回答（1 个）

Chris
Chris 2014-1-23
Hey Siem,
I would do it like this:
v = p .* 1:length(p);
  1 个评论
Siem Nijskens
Siem Nijskens 2014-1-23
Hi Cris,
Thanks for answering my question, unfortunately your solution didn't work.
Regards, Siem

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