No, the integral of sin(x) is -cos(x)+C. Now you must solve for C.
If you double click your integrator you will see that you have set your initial condition, y(0) by default to be 0. That is, y(0)=0=-cos(0)+C, so C=1.
If you would like the offset, C, to be zero, then you need to change your equation so that y(0)=-cos(0)+0, therefore y(0)=-1. Double click your integrator block and enter -1 instead of zero for the intial condition.
