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Techit
Techit 2011-7-12
I want to ask about matlab's code of this clip >>http://www.youtube.com/watch?v=EbC0eP0Dq9A<<
Step for Algorithm .. 1. fix number of point for random . 2. when it ploted, separate which point in a circle and another out of circle. 3. after point are random finish, calculate ratio in a picture. by Ratio = (Rectangle's areas * all of point in a circle) / number of point for random
Sorry, If I spell grammar wrong..
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Techit
Techit 2011-7-12
yeah, thx for all comments :)
but i need some guild line for a code
because i can't understand that youtube comments
thanks agian
and i'm sorry for my newbie in this matlab

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Paulo Silva
Paulo Silva 2011-7-12
clf
r=1;
rectangle('Position',[-1,-1,2*r,2*r],'Curvature',[1,1])
axis([-1 1 -1 1])
hold on
n=1000;
x=-1+2*r*rand(n,1);
y=-1+2*r*rand(n,1);
plot(x,y,'r.');
in=sum((x.^2+y.^2)<r);
(2*r)^2*in/n %Thanks Sean, (2*r)^2 is the area of the circle
Increasing n gives better approximations for the value of pi.
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Paulo Silva
Paulo Silva 2011-7-12
text(-0.5,1.1,['aproximmated \pi value=' num2str((2*r)^2*in/n)])
Techit
Techit 2011-7-12
Thank you very much for your help.
> ขอบคุณครับ < I'm from Thailand :)

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更多回答（2 个）

Sean de Wolski
Sean de Wolski 2011-7-12
I think the answer to your question is already answered in the video comments.
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Walter Roberson
Walter Roberson 2011-7-12
Shouldn't that be
help rdivide
rather than ldivide ?
Sean de Wolski
Sean de Wolski 2011-7-12
hmmm lt or le? The video says lt, but points on the circumference are part of the circle...

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Sean de Wolski
Sean de Wolski 2011-7-12
Alright - darkness golf
f=@(n)etc
I can do it with 38 characters (lt); 39 (le).

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