why can't I get a vector as an output while using a constant in the function handle ?

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ahmad
ahmad 2014-2-5
评论： Walter Roberson 2014-2-5
I define the following constant function
f=@(x,y)0;
and I define the following vector
z=[1 2; 3 4; 5 6];
I want to evaluate the function f using feval
feval(f,z(:,1),z(:,2));
my question is that why can't I get the output as a vector instead of a scalar ?

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-2-5
编辑：Azzi Abdelmalek 2014-2-5
Because that's what your function do, the result is always 0, it's independent of your inputs
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Azzi Abdelmalek
Azzi Abdelmalek 2014-2-5
编辑：Azzi Abdelmalek 2014-2-5
I will give you a mathematical example
f(t)=10
The output is always 10, give any value for t, the output will not change
f(0)=10
f(100)=10
The same for your function
f=@(x,y)0
The result is independent of x and y, the result will be always 0. you can connect the size of your output to your input by
f=@(x,y) zeros(size(x))
or
f=@(x,y) x*0

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Walter Roberson
Walter Roberson 2014-2-5
f = @(x,y) zeros(size(x));

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