Storing values in a for loop when input vector is not used in calculation

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B.M.
B.M. 2014-2-7
评论： B.M. 2014-2-7
I'm working through examples in "Matlab for Engineers and Scientists" and am having trouble with this problem:
=============================
Suppose you deposit $50 in a bank account every month for a year. Every month, after the deposit has been made, interest at the rate of 1% is added to the balance: After one month the balance is $50.50, and after two months it is $101.51. Write a program to compute and print the balance each month for a year. Arrange the output to look something like this:
MONTH MONTH-END BALANCE
1 50.50
2 101.51
3 153.02
...
12 640.47
=============================
Obviously the vector of months shows up fine, but I can't get the balance vector figured out...if I used the months vector in the calculation of balance I know I'd get a vector, but my current code overwrites the previous balance from last month. I don't use the months vector for anything but a counter/index:
=============================
Monthly=50;
Months=[1:12];
Balance=0;
for k=1:length(Months)
Balance=(Balance+(Monthly))*1.01;
end
disp('MONTH MONTH-END BALANCE')
disp([Months' Balance'])
=============================
I know I can do this using the month as an exponent on the rate but just want to know if there's a way to get a vector of balances by modifying the code above.

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Amit
Amit 2014-2-7
Monthly=50;
Months=[1:12];
Balance=0;
disp('MONTH MONTH-END BALANCE')
for k=1:length(Months)
Balance=(Balance+(Monthly))*1.01;
disp([Months(k) Balance])
end
  2 个评论
Amit
Amit 2014-2-7
And if you really want to store the values,
Monthly=50;
Months=[1:12];
Balance=zeros(12,1);
Balance(1) = Monthly*1.01;
for k=2:length(Months)
Balance(k)=(Balance(k-1)+(Monthly))*1.01;
end
B.M.
B.M. 2014-2-7
So your first post did the trick. So the problem was that the displayed vectors had to reference the index k, and that statement had to be in the for loop?

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