What's wrong with my feature extraction code?

2 次查看（过去 30 天）

显示更早的评论

Explorer 2014-2-12

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/115842-what-s-wrong-with-my-feature-extraction-code

关闭： MATLAB Answer Bot 2021-8-20

在 MATLAB Online 中打开

I am getting same descriptors for different images.

I tested it by:

image1 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\A.jpg');

image2 = imread('C:\Users\Explorer\Documents\MATLAB\ASL_signs\B.jpg');

v1=Descrip(image1);

v2=Descrip(image2);

SUM=sum(v1-v2)

_____________________________________________________________________________________

Output :

SUM =

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Explorer 2014-2-12

There is something wrong in Descrip.m because I am getting zero for SUM=sum(v1-v2). Ideally, it should not be zero.

此问题已关闭。

回答（2 个）

David Young 2014-2-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/115842-what-s-wrong-with-my-feature-extraction-code#answer_124096

Descrip writes then reads contour.jpg, and then computes the result from that. One way to set about debugging would be to see whether contour.jpg is different for the two images. That will help pin down where the problem lies.

4 个评论
显示 2更早的评论隐藏 2更早的评论

Explorer 2014-2-12

编辑：Explorer 2014-2-12

But sum is not equal to equal when I replace "1" with "2" in line # 57 of Descrip.m and Descrip2.m

i.e

________________________________________________________________________

Original

thisBoundary = boundary{1}; % Or whatever blob you want.

________________________________________________________________________

Replaced

thisBoundary = boundary{2}; % Or whatever blob you want.

David Young 2014-2-13

The idea was that you run Descrip with one input image, look at contour.jpg, run it again with the other input image, and look at contour.jpg again. Are they different?

Image Analyst 2014-2-12

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/115842-what-s-wrong-with-my-feature-extraction-code#answer_124141

编辑：Image Analyst 2014-2-12

Don't use image as a variable name - it's the name of a built-in function.

5 个评论
显示 3更早的评论隐藏 3更早的评论

Image Analyst 2014-2-13

If image A equals image B then I think they should be the same. You didn't attach either image so only you can know that. What did stepping through with the debugger reveal to you?

Walter Roberson 2014-2-13

Watch out for the case where v1 and v2 are being returned as unsigned integers; in that case if v2 > v1 you would get "clipping" at 0 instead of getting a negative number.

此问题已关闭。