Converting base 10 to base 2, dec2base help

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Jarred
Jarred 2014-2-13
编辑： Walter Roberson 2021-11-21
So I am writing a script to convert a number from base 10 to base 2. I have written my own script, but I had trouble using dec2base. The function does not seem to work when I write something like
(i = dec2base(4, 2); and also fprintf('%g', i))
It outputs 494848. However, if I simply write dec2base(4, 2) without a semicolon the operation works, but the format is wrong.

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采纳的回答

Jos (10584)
Jos (10584) 2014-2-13
X = dec2base(4,2)
whos X % X is a character array!
fprintf('%g', X) % prints out ascii codes of the string!, Similar to ...
fprintf('%g', 'hello')
fprintf('%s', X) % use %s as a format string for character arrays

更多回答（2 个）

Walter Roberson
Walter Roberson 2014-2-13
bits_wanted = 16;
i = dec2base(4, 2, bits_wanted);
fprintf(i);
Sagar Damle
Sagar Damle 2014-2-13
编辑：Walter Roberson 2021-11-21
In MATLAB, either a comma(,) or a semi colon(;) separates two statements. Semi colon doesn't print the answer.
I think,you will require a 'number' in base 2 format and not a 'string'(i.e. character array).There are many functions in MATLAB to convert base 10 to base 2 of a number –
1. dec2base()
2. dec2bin()
3. de2bi()
4. dec2binvec()
However,outputs of these are are not in same format. Run this code on your computer for understaning purpose. See help about these functions in MATLAB.
Note : '0' represents ASCII value of zero(0) which is 48. So,
ans2 = dec2base(4,2) - '0'
is same as
ans2 = dec2base(4,2) – 48
Play with these functions! ENJOY!
% Program -
temp1 = dec2base(4,2)
ans1 = str2num(dec2base(4,2))
ans2 = dec2base(4,2) - '0'
temp2 = dec2bin(4)
ans3 = dec2bin(4) - '0'
temp3 = de2bi(4)
temp4 = de2bi(4,'right-msb')
ans4 = de2bi(4,'left-msb')
temp5 = dec2binvec(4)
ans5 = seqreverse(dec2binvec(4))
whos

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