How can I convert this circle drawing code as a Function code? thank you

Question

Maitham 2014-2-14

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116108-how-can-i-convert-this-circle-drawing-code-as-a-function-code-thank-you

回答： Maitham 2014-2-16

% Create a logical image of a circle with specified
% diameter, center, and image size.
% First create the image.
imageSizeX = 640;
imageSizeY = 480;
[columnsInImage rowsInImage] = meshgrid(1:imageSizeX, 1:imageSizeY);
% Next create the circle in the image.
centerX = 320;
centerY = 240;
radius = 100;
circlePixels = (rowsInImage - centerY).^2 ...
    + (columnsInImage - centerX).^2 <= radius.^2;
% circlePixels is a 2D "logical" array.
% Now, display it.
image(circlePixels) ;
colormap([0 0 0; 1 1 1]);
title('Binary image of a circle');

[EDITED, Jan, code formatted]

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Answer 1

Mischa Kim 2014-2-14

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/116108-how-can-i-convert-this-circle-drawing-code-as-a-function-code-thank-you#answer_124340

编辑：Mischa Kim 2014-2-14

在 MATLAB Online 中打开

Maitham, check out the following:

function my_circ(imageSize, center, radius)  % function definition
% Create a logical image of a circle with specified 
% diameter, center, and image size. 
% First create the image.
imageSizeX = imageSize(1);
imageSizeY = imageSize(2);
[columnsInImage rowsInImage] = meshgrid(1:imageSizeX, 1:imageSizeY);
% Next create the circle in the image.
centerX = center(1);
centerY = center(2);
circlePixels = (rowsInImage - centerY).^2 ...
    + (columnsInImage - centerX).^2 <= radius.^2;
% circlePixels is a 2D "logical" array.
% Now, display it.
image(circlePixels) ;
colormap([0 0 0; 1 1 1]);
title('Binary image of a circle');
end   % end of function