How can I manage with this numbers?

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Francesco
Francesco 2014-2-22
评论： Dishant Arora 2014-2-22
I have a A=1x56 double variable.
A =
Columns 1 through 9
0.0127 0.0358 0.2141 0.2279 0.2737 0.0003 0.0282 0.0196 0.0307
Columns 10 through 18
0.2148 0.1049 0.1963 0.1725 0.0442 0.0279 0.0485 0.0659 0.0735
Columns 19 through 27
0.0285 0.0593 0.0568 0.1611 0.0540 0.4560 0.3430 0.2006 0.0439
Columns 28 through 36
0.1192 0.1400 0.0719 0.1776 1.6570 0.5565 0.6836 0.1456 0.0308
Columns 37 through 45
0.7118 0.3418 0.4893 0.3433 0.0241 0.2332 0.1560 0.0538 0.5159
Columns 46 through 54
0.0075 0.0640 0.0411 0.0219 0.0245 0.0294 1.1100 0.1268 0.2686
Columns 55 through 56
0.0543 0.0266
But In general I work with 1xn double variable. After this I have
col_A=rc1(1,2)-2;
But col_A it's simple a number: 7 for example in this case. I have to create a matrix that is an made up by 7 columns and 8 rows, in this case because the number of columns depends of the col_A value and The number of rows depends is n/col_A value. How Can I do this?
  2 个评论
Mischa Kim
Mischa Kim 2014-2-22
I am not quite clear on what you are trying to do. What is rc1?
Francesco
Francesco 2014-2-22
Do not consider rc1 but only col_A. It's not important rc1. It's another constant defined before in the code. I have to create another matrix from A 1x56 double. But this matrix is made up by the same element of 1x56 or 1xn in the general case. Now A is a row vector. Good, I would like to obtain also an array. I have to obtain a matrix has to be made that we need to go over again every col_A. If you do this then we have a 8x7 array. Is it clear now?

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Dishant Arora
Dishant Arora 2014-2-22
编辑：Dishant Arora 2014-2-22
what's rc1?? anways try this:
row_A = n/col_A;
reshape(A, row_A, [] );
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Francesco
Francesco 2014-2-22
I can put lenght(A)for a generalization case?

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