Can Anyone help me with the source of comparing histograms of images using Chi-Square Distance?? I searched online i got but it is giving me zero distance reagardless of histograms are same or not. I.e. Matching or not matching.. Please help me.

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radha
radha 2014-2-22
评论： radha 2014-2-22
function d=chi_square_statistics(XI,XJ) % Implementation of the Chi^2 distance to use with pdist % (cf. "The Earth Movers' Distance as a Metric for Image Retrieval", % Y. Rubner, C. Tomasi, L.J. Guibas, 2000) % % @author: B. Schauerte % @date: 2009 % @url: http://cvhci.anthropomatik.kit.edu/~bschauer/
% Copyright 2009 B. Schauerte. All rights reserved.
%
% Redistribution and use in source and binary forms, with or without
% modification, are permitted provided that the following conditions are
% met:
%
% 1. Redistributions of source code must retain the above copyright
% notice, this list of conditions and the following disclaimer.
%
% 2. Redistributions in binary form must reproduce the above copyright
% notice, this list of conditions and the following disclaimer in
% the documentation and/or other materials provided with the
% distribution.
%
% THIS SOFTWARE IS PROVIDED BY B. SCHAUERTE ''AS IS'' AND ANY EXPRESS OR
% IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
% WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
% DISCLAIMED. IN NO EVENT SHALL B. SCHAUERTE OR CONTRIBUTORS BE LIABLE
% FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
% CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF
% SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR
% BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY,
% WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR
% OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF
% ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
%
% The views and conclusions contained in the software and documentation
% are those of the authors and should not be interpreted as representing
% official policies, either expressed or implied, of B. Schauerte.
m=size(XJ,1); % number of samples of p
p=size(XI,2); % dimension of samples
%assert(p == size(XJ,2)); % equal dimensions
%assert(size(XI,1) == 1); % pdist requires XI to be a single sample
d=zeros(m,1); % initialize output array
for i=1:m
for j=1:p
m=(XI(1,j) + XJ(i,j)) / 2;
if m ~= 0 % if m == 0, then xi and xj are both 0 ... this way we avoid the problem with (xj - m)^2 / m = (0 - 0)^2 / 0 = 0 / 0 = ?
d(i,1) = d(i,1) + ((XI(1,j) - m)^2 / m); % XJ is the model! makes it possible to determine each "likelihood" that XI was drawn from each of the models in XJ
end
end
end
  2 个评论
radha
radha 2014-2-22
Please Tell me what should I do so that I can differentiate when histograms are matching and not matching?? Because It gives me zero distance for both so I have no idea how should go ahead?? Thanks in advance... Please help me as soon as possible..

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