calculation of successive diffrence

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Rica
Rica 2014-2-27
回答： Anuj 2014-2-27
Hi all!
I have a problem with this : I have an array:
% A=[a1 a2 a3 a4 ......an]
i want to calculate succesivelly the diffrenece:
% B=[a2-a1 a3-a2 a4-a3........] but with this condition:
if for exemple a(i)-a(i-1)==2, the diffrence a(i+1)-a(i-1) schould be calculated and the diffrence a(i)-a(i-1)==2 should be eleminated from the Array B.
i wish you could help , Thank you
  1 个评论
the cyclist
the cyclist 2014-2-27
编辑：the cyclist 2014-2-27
Often in these cases, a small (but complete) example helps to illustrate what you mean. For example, what should the output be if
A = [2 3 5 7 11 13 17 19]
?
The way I am interpreting your question must be wrong, because I would calculate every difference, but then remove every difference from B, leaving an empty matrix.

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2014-2-27
B = diff(A);
B1 = conv(A,[1 0 -1],'valid');
idx = find(B == 2);
ii = idx <= numel(B1);
i2 = idx(ii);
B(i2) = B1(i2);

更多回答（1 个）

Anuj
Anuj 2014-2-27
B = diff(A);
B(find((B==2))=B(find(B==2)+1)+2

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