Consider only a positive numbers of the first columns.

2 次查看(过去 30 天)
I have this matrix:
A =
-0.0001 -0.0723 0.0007 0.0013 -0.0007 -0.0016 -0.0009 0.0010 -0.0018
-0.0004 -0.0723 0.0008 0.0012 -0.0008 -0.0017 -0.0009 0.0011 -0.0017
-0.0005 -0.0723 0.0007 0.0013 -0.0008 -0.0017 -0.0009 0.0011 -0.0017
0.0002 -0.0723 0.0007 0.0012 -0.0007 -0.0017 -0.0009 0.0010 -0.0018
-0.0003 -0.0723 0.0006 0.0012 -0.0007 -0.0017 -0.0009 0.0011 -0.0017
0.0005 -0.0723 0.0007 0.0013 -0.0007 -0.0017 -0.0009 0.0011 -0.0017
My issue is to by-pass (or not consider) the rows that start with a negative number in the first column. How can I extend this procedure if I work with cell or struct variable? How can I do it?

采纳的回答

Mischa Kim
Mischa Kim 2014-3-1
编辑:Mischa Kim 2014-3-1
Use
B = A(find(A(:,1)>0),:)
Concerning your second question: that, of course, depends on how your cell array looks like. In general, you could convert to a numeric array and then use the code above.
  5 个评论
Mischa Kim
Mischa Kim 2014-3-1
Well, as I said, it depends on how your cell array looks like. So for the one you're posting in your comment: do you want to treat the 8 different arrays as independent ones with regards to ignoring rows that start with a negative number in the first column? Or is this supposed to be one large 1000-by-72 matrix?
Francesco
Francesco 2014-3-1
It's not supposed to be one marge 1000 by 72 matrix. But I would like to to the same procedure you said for each one of the 8 (or n) different arrays. As you said I want to: "treat the 8 different arrays as independent ones with regards to ignoring rows that start with a negative number in the first column"

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by