Problem Integrating sin(2*x)
5 次查看(过去 30 天)
显示 更早的评论
>> syms x >> f=sin(2*x)
f =
sin(2*x)
>> int(f)
ans =
sin(x)^2
>>
I am sure it is wrong because it should be -1/2+sin(x)^2
0 个评论
采纳的回答
Paul
2014-3-5
The integral is:
sin(x)^2 + C
but Matlab just doesn't show the constant. How do you get the -1/2? Because if you differentiate the integral (sin(x)^2 + C) you get:
2*sin(x)*cos(x) = sin(2*x)
And the constant differentiated gives 0 since it doesnt depend on x.
4 个评论
Gustavo Leal
2017-10-9
sin(pi)^2 != -cos (2pi)/2 ,for example, something its wrong with this function at MATLab
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!