Generating random integer from -x to x

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I need to find a way to generate a random integer from -x to x for example -5 to 5

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Chris C
Chris C 2014-3-12
编辑:Chris C 2014-3-12
xmin = -x;
xmax = x;
r = round((xmax-xmin).*rand(10,1)+xmin);

更多回答(1 个)

per isakson
per isakson 2014-3-12
编辑:per isakson 2014-3-12
2*x*rand-x produces uniformly distributed numbers
Doc says: Example 1, Generate values from the uniform distribution on the interval [a, b]:
r = a + (b-a).*rand(100,1);

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