split a n*m-by-1 vector into n m-by-1 vectors

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jimaras
jimaras 2014-3-14
评论： Star Strider 2014-3-14
I would like to split a m*n-by-1 vector into smaller ones, e.g. m-by-1. I have tried to think of an efficient way but i have not.
Any ideas?
Thank you.

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采纳的回答

Star Strider
Star Strider 2014-3-14
I suggest reshape:
A=[1; 2; 3; 4; 5; 6; 7; 8];
B = reshape(A,2,4)
The columns of B are your 2x1 vectors:
B =
1.0000e+000 3.0000e+000 5.0000e+000 7.0000e+000
2.0000e+000 4.0000e+000 6.0000e+000 8.0000e+000

更多回答（2 个）

Benjamin Avants
Benjamin Avants 2014-3-14
I think the easiest method uses num2cell:
myArray = ones(3,4,1);
myCell = num2cell(myArray,1)
ans =
[3x1 double] [3x1 double] [3x1 double] [3x1 double]
You then have a 4 element cell array of 3x1 numerical arrays. Not sure if that's what you're looking for, but perhaps its a step in the right direction. The second parameter of num2cell determines which dimension is split into cells. Making that argument a 2 would yield a 3 element cell array of 4x1 numerical arrays.
  1 个评论
jimaras
jimaras 2014-3-14
Basically, no. Maybe I didn't post the question correctly. I have the following vector:
A=[1; 2; 3; 4; 5; 6; 7; 8]
and I want to split it into 4 smaller ones (2x1) how can I do this.
P.s. Number are chosen randomly.

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Joseph Cheng
Joseph Cheng 2014-3-14
How about putting it into the 3rd dimension? A=reshape(A,2,1,4) then you can reference A(:,:,1) to A(:,:,4) will be the smaller ones?

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