split a n*m-by-1 vector into n m-by-1 vectors
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I would like to split a m*n-by-1 vector into smaller ones, e.g. m-by-1. I have tried to think of an efficient way but i have not.
Any ideas?
Thank you.
采纳的回答
Star Strider
2014-3-14
I suggest reshape:
A=[1; 2; 3; 4; 5; 6; 7; 8];
B = reshape(A,2,4)
The columns of B are your 2x1 vectors:
B =
1.0000e+000 3.0000e+000 5.0000e+000 7.0000e+000
2.0000e+000 4.0000e+000 6.0000e+000 8.0000e+000
更多回答（2 个）
Benjamin Avants
2014-3-14
I think the easiest method uses num2cell:
myArray = ones(3,4,1);
myCell = num2cell(myArray,1)
ans =
[3x1 double] [3x1 double] [3x1 double] [3x1 double]
You then have a 4 element cell array of 3x1 numerical arrays. Not sure if that's what you're looking for, but perhaps its a step in the right direction. The second parameter of num2cell determines which dimension is split into cells. Making that argument a 2 would yield a 3 element cell array of 4x1 numerical arrays.
Joseph Cheng
2014-3-14
0 个投票
How about putting it into the 3rd dimension? A=reshape(A,2,1,4) then you can reference A(:,:,1) to A(:,:,4) will be the smaller ones?
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