struct and cell ,is there a way like dictionary in struct
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if true
end
station = struct(...
'name', {'CD2','GYA','LZH','GOM','XAN'},...
'Jingdu',{103.76 ,106.66,103.84,94.81,108.92},...
'Weidu',{30.91, 26.46, 36.09, 36.20, 34.03});
p={'CD2','GYA','LZH','GOM','XAN'};
now i pick one from p,how can i get the one 's Jingdu?
采纳的回答
Jos (10584)
2014-3-17
You mean something like this?
station = struct(...
'name', {'CD2','GYA','LZH','GOM','XAN'},...
'Jingdu',{103.76 ,106.66,103.84,94.81,108.92},...
'Weidu',{30.91, 26.46, 36.09, 36.20, 34.03});
p={'CD2','GYA','LZH','GOM','XAN'};
K = 2 ; % pick one
TF = strcmp({station.name}, p{K}) % true when station.name equals p{K}
Result = [station(TF).Jingdu]
更多回答（1 个）
Roger
2014-3-17
0 个投票
1 个评论
Walter Roberson
2014-3-17
[tf, k] = ismember('GYA', station.name);
if tf
disp(station.Jingdu(k))
else
disp('no match')
end
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