how to find the integral of F = x./(1+x.^4) on matlab
2 次查看(过去 30 天)
显示 更早的评论
how to find the integral of F = x./(1+x.^4) on matlab in the range of 0 and 5 i have used the following; int(F,x,0,6)
but an error of "Undefined function 'int' for input arguments of type 'double'." comes up.
1 个评论
Roger Stafford
2014-3-27
Note that this a problem you don't really need matlab for. A calculus student would tell you to substitute y = x^2 to produce the integral of 1/2/(1+y^2) with respect to y from y = 0 to y = 6^2 which gives you 1/2*atan(36).
回答(2 个)
John D'Errico
2014-3-27
IF you have the symbolic toolbox, then do this:
syms x
int(x/(1+x^4),x,0,6)
ans =
atan(36)/2
If not, then do it numerically.
format long g
integral(@(x) x./(1 + x.^4),0,6)
ans =
0.771512845100738
Note that the numerical solution happens to match the symbolic one. A good thing, really.
atan(36)/2
ans =
0.771512845100738
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Calculus 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!