solve matlab equation( 512*512*log2(B))/2>==520000
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sir i am new to this matlab i want to satisfy the equation (512*512*log2(B))/>=520000 by keeping what value of B this equation will be satisfied answer is 16 .. i want how to do code for this equation in matlab by taking B values automatically to satisfy this equation
回答(2 个)
A Jenkins
2014-4-2
syms B
sym_b=solve(512*512*log2(B)/2==520000)
vpa(sym_b)
ans =
15.641263534925078400119749631703
5 个评论
vaka sindhu
2014-4-2
Walter Roberson
2014-4-2
编辑:Walter Roberson
2014-4-2
The answer is 15.641263534925078400119749631703 approximately, and "A Jenkins" shows one way it can be calculated.
vaka sindhu
2014-4-2
vaka sindhu
2014-4-2
A Jenkins
2014-4-2
In older versions of MATLAB, you can try rearranging:
sym_b=solve((512*512*log2(B))/2-520000)
Star Strider
2014-4-2
The easiest way is to take the base-2 antilog of both sides. You get the answer directly:
B = 2^(2*520000/(512^2))
gives:
B =
15.6413e+000
1 个评论
A Jenkins
2014-4-2
That was going to be my next proposal too, but then we are just teaching math, and not "code for this equation in matlab by taking B values automatically to satisfy this equation".
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