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replace array numbers in places that are not the indices of another array

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Alon
Alon 2014-4-10
回答： Alon 2014-4-10
Hello, I have array_1 looks like this: array_1=[4 7 22 44 13 4 1 9 6 0 5 77 45 12];
I have another array -> array_2=3:7;
I need to write a code such that the indices of array_1 which are represented in array_2 will stay as they are and all the others will replaced by zeroe so I can get:
array_1=[0 0 22 44 13 4 1 0 0 0 0 0 0 0];
Help please! Thanks

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-4-10
array_1=[4 7 22 44 13 4 1 9 6 0 5 77 45 12];
array_2=3:7
array_3=zeros(size(array_1))
array_3(array_2)=array_1(array_2)

更多回答（1 个）

Alon
Alon 2014-4-10
Amazing!

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