Taking unique numbers of a set and order them with their respective number
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Hello, I have a question i need hel with,
if i have this two vectors that go with each other
angle= [0; 1; 5; 3; 7; 8; 6; 9; 2; 4; 0]
radius= [ 2; 4; 6; 7; 8; 9; 6; 4; 3; 3; 2]
For example angle 0 goes with radius 2, angle 1 goes with radius 4 and so on... I want to take away the repeated angles and order them from smaller to bigger and keep their respective radius with them to get something like this
angle= [ 0; 1; 2; 3; 4; 5; 6; 7; 8; 9]
radius= [ 2; 4; 3; 7; 3; 6; 6; 8; 9; 4]
I really need help with this thank you very much
采纳的回答
Sean de Wolski
2014-4-18
unique will be your friend:
angle= [0; 1; 5; 3; 7; 8; 6; 9; 2; 4; 0];
radius= [ 2; 4; 6; 7; 8; 9; 6; 4; 3; 3; 2];
% unique angles and index of first occurence
[uv,id,~] = unique(angle);
% extract
ang = uv
rad = radius(id)
更多回答（3 个）
Walter Roberson
2014-4-18
ar = unique([angle, radius], 'rows');
angle = ar(:,1);
radius = ar(:,2);
dpb
2014-4-18
>> unique([angle radius],'rows')
ans =
0 2
1 4
2 3
3 7
4 3
5 6
6 6
7 8
8 9
9 4
>>
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