Scatter plot does not display point 0,0 when double precision
显示 更早的评论
I have the following code which works as intended, plotting 3 points.
x = [0 0; 12 0; 6 6];
scatter(x(:,1), x(:,2), 100, 'fill');
However, when I interject the following line
x = 1.01 * x;
which effectively turns everything into double precision, then the point 0,0 does not display
why is that, and how can I make it so that it also displays?
Thanks in advance!
采纳的回答
José-Luis
2014-4-23
Trying to understand the mess that is Matlab's graphics engine is a real pain. I can only recommend a workaround:
x = [0 0; 12 0; 6 6];
figure(1)
scatter(x(:,1), x(:,2), 100, 'fill');
x = 1.01 * x;
figure(2)
scatter(x(:,1), x(:,2), 100, 'fill'); %Now readjust the axes so you can see what you actually plotted:
set(gca,'XLim',x([1 2],1)); %you can use min() max() in order to avoid hard coding the indices.
set(gca,'YLim',x([1 3],2));
更多回答（3 个）
AJ von Alt
2014-4-23
This looks like an issue with the Painters renderer. Switching to OpenGL resolves the issue on my end.
x = [0 0; 12 0; 6 6];
figure('renderer','OpenGL')
scatter(x(:,1), x(:,2), 100, 'fill');
y = 1.01 * x;
figure('renderer','OpenGL')
scatter(y(:,1), y(:,2), 100, 'fill');
2 个评论
chris
2014-4-23
AJ von Alt
2014-4-23
The renderer is used to draw the plot in the figure. It is defined independently for each figure so you will need to specify it every time you create one.
You can change the renderer of the current figure to "OpenGL" using the command:
set( gcf , 'renderer' , 'OpenGL' )
To read more about renderers see: http://www.mathworks.com/help/releases/R2013b/matlab/ref/figure_props.html#Renderer
chris
2014-4-23
0 个投票
Thanks for your answer. Attached image is how my system behaves.
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