why when i make conv between an averaging filter and a noisy circuit it doesn't get filtered?

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amira ramadan
amira ramadan 2014-4-29
评论： amira ramadan 2014-5-3
n=0:499
x=sin(2*pi*n/50)
y=x+0.1*randn(size(n))
h=[11111]/5
z=conv(h,y)

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采纳的回答

Image Analyst
Image Analyst 2014-4-29
You need commas between the ones in h:
n=0:499
x=sin(2*pi*n/50)
y=x+0.1*randn(size(n))
h=[1,1,1,1,1]/5
z=conv(h,y)

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Andrei Bobrov
Andrei Bobrov 2014-4-29
编辑：Andrei Bobrov 2014-4-29
n=0:499;
x=sin(2*pi*n/50);
y=x+0.1*randn(size(n));
h=[1,1,1,1,1]/5;
z=conv(y,h,'same');
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