matlabpool open n; doesn't work.

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Martin
Martin 2014-5-7
评论： Bruno Silva 2020-1-17
Hi,
I'd like to open matlabpool with a variable number of cores, to use the maximum number of cores available. So n would equal features('numCores') here.
But matlabpool open n, matlabpool open features('numCores'), matlabpool open maxNumCompThreads don't work here. matlabpool open seems to accept only numbers and not variables.
I could do something stupid like
if features('numCores') == 4
matlabpool open 4;
elseif features('numCores') == 2
matlabpool open 2;
end
but I'd like to know if something more elegant exists.
Thanks!

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采纳的回答

Niklas Nylén
Niklas Nylén 2014-5-7
编辑：Niklas Nylén 2014-5-7
This is because writing arguments like this:
matlabpool open 2
is the same as passing the strings 'open' and '2' to the matlabpool function, i.e. the equivalent to
matlabpool('open','2')
What you can do is to call matlabpool like this:
matlabpool('open', num2str(features('numCores')))
Possibly you can also pass the number of cores directly, but since I do not have parallell computing toolbox I can't test it, like so:
matlabpool('open', features('numCores'))

更多回答（2 个）

Matt J
Matt J 2014-5-7
编辑：Matt J 2014-5-7
If you have R2013b or later, you shouldn't be using matlabpool . You should be using parpool , which does take a variable as input directly,
parpool(n)
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显示 1更早的评论
Haseeb Hassan
Haseeb Hassan 2018-10-7
Thank you Matt for your useful hint.

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Malshikho
Malshikho 2018-5-25
Unfortunately I have Matlab R2010b
  1 个评论
Steven Lord
Steven Lord 2018-5-25
Then use matlabpool using the syntax described in the accepted answer by Niklas Nylén.

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