fft and random sequence

4 次查看(过去 30 天)
yasser
yasser 2014-5-9
回答: yasser 2014-5-10
generating 2 random sequences with randn with same variance then applying fft to them would result in 2 sequences of non = variances why is that

回答(3 个)

the cyclist
the cyclist 2014-5-9
Because the sample variance is not necessarily equal to the population variance.
  2 个评论
yasser
yasser 2014-5-9
please explain more
the cyclist
the cyclist 2014-5-9
Here is the simplest possible explanation I can think of. Imagine you use the command
randn(2,1)
to draw a sample with two values from a distribution that is N(0,1). (In other words, a normal distribution with population mean of 0 and standard deviation of 1.)
Suppose that draw gives you values of [0.7824 -0.5000]. The sample mean of that sample is 0.1412. The sample standard deviation is 0.9068.
Do you get upset that the sample mean is not exactly zero, and that the sample standard deviation is not exactly 1? Hopefully not. It's a random sample, with random variation.
Similarly in your example, there is random variation.

请先登录,再进行评论。


Star Strider
Star Strider 2014-5-9
The Fourier transform integrates over the original x variable, so the Fourier transform is a function of the (complex) frequency variable only. You are taking the mean and standard deviation (variance) of F(w) rather than f(x).
So if you have different lengths of the vectors in the original ( x or t ) domain, the means and variances should be close to the same in that domain. Without appropriate scaling for different lengths or sampling frequencies, the means and variances (taken over the frequency variable) of the Fourier transforms of those data would not be the same in the complex frequency domain.
I’m not certain what you did, so this is only theoretical. The analytical maths are not trivial, and neither the Symbolic Math Toolbox or my back-of-the-envelope analysis yielded a definitive answer.

yasser
yasser 2014-5-10
thanks u all

类别

Help CenterFile Exchange 中查找有关 Fourier Analysis and Filtering 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by