Integration of velocity not working, creating zeros
1 次查看(过去 30 天)
显示 更早的评论
%%Calculation of Velocity and Acceleration
v(i,1)= trapz(jh(i,1));
a(i,1)= trapz(v(i,1));
This is what I am using for differentiation. But both of these are coming out in the workspaces as zero... I don't know what this is. jh is jump height, there are numbers for this
0 个评论
采纳的回答
dpb
2014-5-15
trapz is an trapezoidal INTEGRATION routine, not differentiation
doc trapz
doc diff
2 个评论
dpb
2014-5-15
编辑:dpb
2014-5-16
"not working" is NEVER sufficient explanation for a problem.
But, if v is velocity and a acceleration, then you're going the wrong way physically.
a=dv/dt --> v=Int(a dt)
As for the zero result, looks like jh(i,1) is a single point so there's nothing to integrate over (even though you need to be differentiating instead it would appear).
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!