Graph analysis question
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I have this data:
X = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21
With
Y = 0.5 1 1.5 2 2.5 3 3.5 4 1 1.5 3 3.5 4.5 5.5 6 2 4 4.5 5.5 6.5 8
This may be more of a math question rather than a matlab question. If you plot the above data you will see three distinct sets of data, is there any way I can get matlab to automatically split this data into the three seperate variables. The number of variables may change depending on the data set, the data I have provided is indicative for the real data the X axis is actually dates.
In short I need Matlab to detect how many separate data sets there are and split the data into different variables.
I've tried using a max and min point script but I didn't get very far with it.
Thanks in advance
3 个评论
the cyclist
2011-8-3
Robert, if you do plot(X,Y,'.'), you will understand better what he means. The data lie in three well defined linear groups.
采纳的回答
the cyclist
2011-8-3
After I posted my answer about cluster analysis, I noticed the following:
Are your (X,Y) data always sorted as in your example, or can the pairs be jumbled? If they are always sorted, you can just look for negative jumps in Y, using the find() and diff() commands, and separate the data wherever there is such a jump downward.
X = [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21];
Y = [0.5 1 1.5 2 2.5 3 3.5 4 1 1.5 3 3.5 4.5 5.5 6 2 4 4.5 5.5 6.5 8];
N = numel(Y);
negativeJumpIndex = find(diff([0,Y])<0);
numberNegativeJumps = numel(negativeJumpIndex);
numberClusters = numberNegativeJumps + 1;
indexToNewLine = [1 negativeJumpIndex N+1];
IDX = zeros(N,1);
for nc=1:numberClusters
IDX(indexToNewLine(nc):indexToNewLine(nc+1)-1) = nc;
end
figure
gscatter(X,Y,IDX)
更多回答(2 个)
the cyclist
2011-8-3
What you are asking about is generically known as "cluster analysis", and MATLAB does have some functionality for it, at least in the Statistics Toolbox. If you have that toolbox, look at "doc kmeans" as a possible starting point.
1 个评论
the cyclist
2011-8-3
I put this answer up before I plotted out your data. Not sure that kmeans() is going to help you, because I think it is always searching for a "nearest neighbors" sort of clustering, rather than the linear groups you have. It seems to me that you have a fairly specialized problem here, and you'll likely need to write custom code for it.
Wolfgang Schwanghart
2011-8-3
I just tried your example. While results of a kmeans clustering don't look too promising, the function clusterdata works quite well. What you should know a priori is the number of clusters in your data.
x = [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21]';
y = [0.5 1 1.5 2 2.5 3 3.5 4 1 1.5 3 3.5 4.5 5.5 6 2 4 4.5 5.5 6.5 8]';
IDX = clusterdata([x y],'distance','chebychev','maxclust',3);
gscatter(x,y,IDX)
Regards, W.
2 个评论
the cyclist
2011-8-3
kmeans() seems to do better than clusterdata() to me, although neither very acceptably well. kmeans() at least gets most of the points attributed to the correct lines. clusterdata() combines almost all of the middle and right-hand lines into one cluster (at least with the syntax you provided).
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