how to plot conditional statement like when Vin=1, Vout=exp(-t/tn) and for Vin =0, Vout=1-exp(-t/tp) where Vin is a periodic square pulse.
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i have tried as follows:
f=input('please enter the value of time');
t = 0:.00001*f:(1-.00001)*f;
fm=2/f;
Vin = .5+0.5*square(2*pi*fm*t);
subplot(211);
plot(t,Vin)
Vdd=5;
Rn=2000;
Rp=3000;
C=0.1e-9;
Tn=Rn*C;
Tp=Rp*C;
V1=Vdd.*(exp(-t/Tn));
V0=Vdd*(1-exp(-t/Tp));
Vout=V1;
Vout(Vin<1)=V0(Vin<1);
subplot(212)
plot(t,Vout)
the problem is that for very small value of f, like f=.00000001 the desired graph is not obtained. Even for values like f=0.001, the gradual decay or rise that is expected is not obtained. please help.
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回答(2 个)
David Sanchez
2014-5-16
statement like when Vin=1, Vout=exp(-t/tn) and for Vin =0, Vout=1-exp(-t/tp):
if (Vin == 1)
Vout=exp(-t/tn);
elseif (Vin == 0)
Vout=1-exp(-t/tp);
end
Image Analyst
2014-5-16
Can't you just use a convolution, conv(), or filter()? Invert the signal and apply a kernel that only looks to the left. Seems pretty straightforward.
2 个评论
Image Analyst
2014-5-16
See Star's code which uses filter(). It is fine. No need to worry about conv() now that you have the filter() code.
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