Question about 3D point intersection

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Brian
Brian 2014-5-16
编辑： Matt J 2014-5-19
Hello, thank you for reading this,
I'm having trouble performing a centroid rotation of a 3D geometry. My data consists of 3D points, and what I want to do is rotate it along its center.
I have the data contained in a Nx3 matrix, where N is my number of points with three column entries for the x, y and z ccordiante respectively. I can rotate it around the origin by multiplying these points by the x, y and z rotation matrices, but the problem is with the rotation comes an extreme translation as well. I want to rotate it along its averaged x, y and z midpoint, so any translation I do doesn't come with a heavy translation of the coordinates.
I looked at some material, but everything I found was for 2D images. I tried applying it to my 3D collection of points, but was unsuccessful. I tried following this as well:
http://www.mathworks.com/matlabcentral/answers/2302-rotation-about-a-point
as it was the closest I can find, but I'm using a 3D geometry, and rotate3d doesn't work the same way as far as I could tell.
Any advice would be appreciated!
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Cedric
Cedric 2014-5-16
编辑：Cedric 2014-5-16
You should start by reading about quaternions. There are plenty of online resources (even videos on youtube!) that will teach you the basics.
Brian
Brian 2014-5-19
Looking now, blimey it looks complicated at first glance. After watching a few tutorials, it still looks complicated, but manageable.
Thanks!

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Cedric
Cedric 2014-5-17
编辑：Cedric 2014-5-19
As suggested by Image Analyst, I am moving my comment here. A good method for rotating points in the 3D space is to use quaternions [ ref, ref ]. I've not used them in a long, long time, so I couldn't recommend a recent, specific resource for learning. However, it is a pretty popular topic, so we find quite a bit of information online. Basically, one advantage of using quaternions over using Euler angles is that the former eliminate a problem named gimbal lock.
I used quaternions with Sysquake and I am unsure how best to use them in MATLAB; there are a few FEX resources, e.g. by Mark Ticknell which includes two demos or a C/MEX version by Steven Michael, .. yet, I have to admit that I don't understand why there is no built-in support in MATLAB base package.
EDIT: here is a basic example, based on FEX/qrot3d. Note that you have to compile it, which means that you have to install a compiler first if not already done.
>> mex -setup
follow the link, install e.g. Windows SDK, relaunch mex -setup and select the SDK when done. Then compile qrot3d:
>> mex qrot3d.c
When done, you have a working qrot3d!
figure(1) ; clf ; hold on ; grid on ;
set( gcf, 'Color', 0.9*[1, 1, 1] ) ;
% - Define data = profile in the x-z plan.
zp = linspace( -10 , 10, 100 ).' ;
xp = 4 + sin( zp/2 ) ;
yp = zeros( size( xp )) ;
data = [xp, yp, zp] ;
% - Rotate profile around z axis.
nHat = [0, 0, 1] ;
for theta = linspace( 0, 3*pi/2, 10 )
quat = [cos(theta/2), sin(theta/2) * nHat] ;
dataRot = qrot3d( data, quat ) ;
plot3( dataRot(:,1), dataRot(:,2), dataRot(:,3), 'b', 'LineWidth', 3 ) ;
end
% - Just for fun, add levels.
alpha = linspace( 0, 3*pi/2, 100 ) ;
for zId = 1 : 2 : 100
xCircle = xp(zId) * cos( alpha ) ;
yCircle = xp(zId) * sin( alpha ) ;
zCircle = zp(zId) * ones( size( alpha )) ;
plot3( xCircle, yCircle, zCircle, 'b' ) ;
end
xlabel( 'x' ) ; ylabel( 'y' ) ; zlabel( 'z' ) ;
set( gca, 'CameraPosition', [10, 5, 10] ) ;
This code outputs
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Brian
Brian 2014-5-19
编辑：Brian 2014-5-19
Thanks again for this, this is a really great example. I have a working interim measure, it will probably take a day or so of pushing my nose against MATLAB to fully understand whats going on here.
What I'm doing in the meantime is the following:
([Mesh points]-[avgx avgy avgz]) * rotationx,y,z + [avgx avgy avgz];
By doing this, I'm still using a euclidean rotation, I'm just translating the mesh to the origin such that the centroid is at [0 0 0]. Then I do my rotation, then translate it back to the centroid it was at. This way, I still have to do the translation, but I can avoid my earlier problem.

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更多回答（1 个）

Matt J
Matt J 2014-5-19
See also this rotation tool
http://www.mathworks.com/matlabcentral/fileexchange/30864-3d-rotation-about-shifted-axis
No idea, though, what you mean by rotation about a point. That is ill-defined, since there are infinite rotation axes passing through any given point.
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Brian
Brian 2014-5-19
编辑：Brian 2014-5-19
I wanted to define a rotation point that wasn't the origin. I ended up doing the following:
([Mesh points]-[avgx avgy avgz]) * rotationx,y,z + [avgx avgy avgz];
By doing this, I'm still using a euclidean rotation, I'm just translating the mesh to the origin such that the centroid is at [0 0 0]. Then I do my rotation, then translate it back to the centroid it was at.
What I wanted to do was automate this rotation around a point such that I didn't need to do a translation, but this method works fine and is relatively fast. I manually specify whether I wanted to rotate along the x, y or z axis (or a combination of the three), and used the corresponding rotation matrices.
Matt J
Matt J 2014-5-19
编辑：Matt J 2014-5-19
The rotation tool at my link allows you to specify a translated axis around which to rotate. No need to translate manually.
Of course, you need to know what axis you want to rotate about and it's still not clear that you do, since you are still speaking of "rotation around a point", which has no clear definition... Rotation in 3D always has to be about an axis, not a point.

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