how to write if statement into for loop?

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lina
lina 2014-5-24
评论： dpb 2014-5-24
Hi all,
I have scattered data and I want to put them together and exclude the other which is not locate along the main axis, the statement of excluded data is
Longitude>43
and the loop is
for i=1:24
t_interp(:,i)=interp1(z(~isnan(z(:,i)),i),t(~isnan(t(:,i)),i),depth);
s_interp(:,i)=interp1(z(~isnan(z(:,i)),i),sal(~isnan(t(:,i)),i),depth);
end
i cant understand how to write it into the loop, I'm appreciate anyone can help me sorry for my bad English thank you in advance
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dpb
dpb 2014-5-24
Think he means to how include the condition, SS...
@lina, what is the variable for Longitude? Need more info...
lina
lina 2014-5-24
the code is for reading data from xls file, Longitude is exists in the file which include 24 stations between 30-45 longitudes the one I dont need it in loop is that >43 which equal to station 4 (by using x=find(Longitude>43) ans=4)
so i need to replace the station 4 values to nan (its also have some nan elements) to interpolate 23 station values
what should i do?

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dpb
dpb 2014-5-24
Need storage arrangement to be precise, but if you have vectors of same length where Longitude is given for each element, then simply
z(Long>43)=nan;
will do the trick. Or, you could simply select the values to operate on and ignore the rest...
zprime=z(Long<43);
If z is a 2D array will need the (:) operator for the alternate dimension to pick up all rows or columns depending on whether the selected index is column or row, respectively.
Look up "logical addressing" in the documentation -- it's a key element of Matlab syntax and utilization.
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dpb
dpb 2014-5-24
So did that solve the problem? If so, how about "Accepting" the answer; if not, show the actual storage scheme.

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