String value and sequently representation

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Akmyrat
Akmyrat 2014-5-27
评论： Image Analyst 2014-5-27
Lets say i have string
M=['XASSANORXOOUOU']
and I want something like this
for i=1:7
Li=[M(i,i+1)]
so that it would give me like this result:
L1=XA
L2=SS
L3=AN
L4=OR
and so on....but this code
Li=[M(i,i+1)]
is not working. Could u help me please.
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Akmyrat
Akmyrat 2014-5-27
yes John, that is the problem for now i can not do it in proper way, i tried this for i=1:7 L=M(2*i,2*i-1) end % but this gives like that answer L=XA, L=SS, L=AN...and so on. but i want it like this L1=XA, L2=SS, L3=AN...

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Geoff Hayes
Geoff Hayes 2014-5-27
编辑：Geoff Hayes 2014-5-27
M is a matrix with a single row, so the code cannot access anything but that first row. As soon as i is greater than 1, then M(i,i+1) will fail with an index out of bounds exception. If you just want to get the pairs, then try something like:
for i=1:2:length(M) % since we are interested in the odd indices only
str = M(i:i+1); % get the two neighbouring characters
end
If you want to print out something like you have above, then just replace the middle line with
fprintf('L%d=%s\n',floor(i/2)+1,M(i:i+1));
If you are trying to save the values at each iteration to a variable named Li then that gets a little more challenging (is it even necessary?).

更多回答（1 个）

rifat
rifat 2014-5-27
编辑：rifat 2014-5-27
M=['XASSANORXOOUOU'];
for i=1:length(M)/2
string=['L' num2str(i) '=M(2*(i-1)+1:2*i)']
eval(string)
end

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