Hi jana,
Try this:
X = [1 2 3 4 5;
3 inf 5 7 inf;
5 6 7 inf inf;
2 3 4 9 1]
[val, rowNum] = min(X,1) % Take the minimum in 1st dimension (columns)
val =
1 2 3 4 1
rowNum =
1 1 1 1 4
As you can see, the minimum value of each column is in val, and the row that it corresponds to is in the rowNum variable.
To get only the last (end) column you can use:
[val, rowNum] = min(X(:,end))
val =
1
rowNum =
4
