Info
此问题已关闭。 请重新打开它进行编辑或回答。
Question regarding matrix index
1 次查看(过去 30 天)
显示 更早的评论
Hi,
I've a following matrix:
[1 2 3 4 5;
3 inf 5 7 inf;
5 6 7 inf inf;
2 3 4 9 1]
I wanted to find the minimum element from the last column with its row and column. So my answer to the above matrix should be 1 (as it is the minimum in column 5), row = 4, column = 5. I dont know how to code this. Please help!
0 个评论
回答(3 个)
Sven
2014-5-28
编辑:Sven
2014-5-28
Hi jana,
Try this:
X = [1 2 3 4 5;
3 inf 5 7 inf;
5 6 7 inf inf;
2 3 4 9 1]
[val, rowNum] = min(X,1) % Take the minimum in 1st dimension (columns)
val =
1 2 3 4 1
rowNum =
1 1 1 1 4
As you can see, the minimum value of each column is in val, and the row that it corresponds to is in the rowNum variable.
To get only the last (end) column you can use:
[val, rowNum] = min(X(:,end))
val =
1
rowNum =
4
Image Analyst
2014-5-28
编辑:Image Analyst
2014-5-28
[minValueInLastCol, rowOfMin] = min(yourMatrix(:, end));
Or if you want the min in the last row (just for completeness in case you're interested):
[minValueInLastRow, colOfMin] = min(yourMatrix(end, :));
0 个评论
Geoff Hayes
2014-5-28
If Z is your matrix from above, just do:
[minVal,minIdx] = min(Z(:,end));
This will return the minimum value in minVal and its index in that column in minIdx:
minVal =
1
minIdx =
4
You already know the column number (5, since last one) and the row number is simply minIdx.
0 个评论
此问题已关闭。
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!