Cell contents assignment to a non-cell array object.

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José
José 2014-5-29
评论： Udit Gupta 2014-5-29
hi.
i dont know why in my code is keeping me sending this error anybody can help me please my code is:
A=input('Dame el sistema de ecuaciones expresado en forma matricial');
b=input('Dame el valor de b');
k=1;
x=input('Dame el valor x0 inicial');
x{1}=x;
r{k}=(A*x{k})-b;
p{k}=-(r{k});
for k=0:10000000000;
alfa{k}=(-(((r{k}')*r{k})/((p{k}')*(A*p{k}))));
x{k+1}=x{k}+(alfa{k}*p{k});
r{k+1}=r{k}+(alfa{k}*A*p{k});
beta{k+1}=((r{k+1})'*r{k})/((r{k}')*(r{k}));
p{k+1}=-(r{k+1})+(beta{k+1}*p{k});
k=k+1;
if (r{k}<=0)
break;
end
end
and the error is the next
*Cell contents assignment to a non-cell array object.*
*Error in gradientesconjugados (line 5)*
*x{1}=x;*
if anybody can help me i would apreciate so much.
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José
José 2014-5-29
i think that i understood you and now i change the code to this because i want to calculate matrices
A=input('Dame el sistema de ecuaciones expresado en forma matricial');
b=input('Dame el valor de b');
k=1;
x0=input('Dame el valor x0 inicial');
r(k)=(A*x0)-b;
p(k)=-(r{k});
but now i get this error
In an assignment A(I) = B, the number of elements in B and I must be the same
if anyone can help me i would apreciate so much.

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2014-5-29
Try this
clear
A=input('Dame el sistema de ecuaciones expresado en forma matricial');
b=input('Dame el valor de b');
k=1;
xx=input('Dame el valor x0 inicial');
x{1}=xx;
r{k}=(A*x{k})-b;
p{k}=-(r{k});
for k=0:10000000000;
alfa{k}=(-(((r{k}')*r{k})/((p{k}')*(A*p{k}))));
x{k+1}=x{k}+(alfa{k}*p{k});
r{k+1}=r{k}+(alfa{k}*A*p{k});
beta{k+1}=((r{k+1})'*r{k})/((r{k}')*(r{k}));
p{k+1}=-(r{k+1})+(beta{k+1}*p{k});
k=k+1;
if (r{k}<=0)
break;
end
end
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José
José 2014-5-29
编辑：José 2014-5-29
a change in the code the xx and the 2 but i get the same error
Cell contents assignment to a non-cell array object.
thanks for your time

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Udit Gupta
Udit Gupta 2014-5-29
Instead of
x=input('Dame el valor x0 inicial');
x{1}=x;
use
temp=input('Dame el valor x0 inicial');
x{1}=temp;
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Udit Gupta
Udit Gupta 2014-5-29
I ran this code without any error. You need to start your loop from k=1 instead of k=0.
A=input('Dame el sistema de ecuaciones expresado en forma matricial');
b=input('Dame el valor de b');
k=1;
temp=input('Dame el valor x0 inicial');
x{1}=temp;
r{k}=(A*x{k})-b;
p{k}=-(r{k});
for k=1:10000000000;
alfa{k}=(-(((r{k}')*r{k})/((p{k}')*(A*p{k}))));
x{k+1}=x{k}+(alfa{k}*p{k});
r{k+1}=r{k}+(alfa{k}*A*p{k});
beta{k+1}=((r{k+1})'*r{k})/((r{k}')*(r{k}));
p{k+1}=-(r{k+1})+(beta{k+1}*p{k});
k=k+1;
if (r{k}<=0)
break;
end
end

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