"@" inside fzero command. I get an erro why?

1 次查看（过去 30 天）
Douglas Alves
Douglas Alves 2014-6-2
评论： Douglas Alves 2014-6-2
I've got 2 .m files. The line which calls the second file is
[f1 q] = fzero(@avaliator,const.guessf1,const)
it'll call avaliator (.m file)
function q = avaliator
e = -100 ;
[r,y] = integrator(const);
q = sqrt((y(end,2)/const.Total_mass)^2 + (r(end)^e/const.Total_Radius)^2)*(y(end,2).../const.Total_mass) ;
the problem is that it only calls avaliator if I take the "@" out. I think it's because of "@" is for calling functions right? But in another code very similar to this "@" is used with no problem and the .m file called is not a function but something like this avaliator file I posted. Does anyone know why it's returning an error? (suppose all the const.'something' known)

请先登录，再回答此问题。

采纳的回答

Matt J
Matt J 2014-6-2
编辑：Matt J 2014-6-2
It's because avaliator is not written to accept an input argument. It needs to be.
function q = avaliator(x)
q=%do something with x
  1 个评论
Douglas Alves
Douglas Alves 2014-6-2
I actually put function q = avaliator(const) in order to const be recognized when it comes in avaliator. But it's not recognized either. I should've put [] between const.guessf1 and const anyways. But it doesn't change anything. lol I think I've got multiples errors here..

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Startup and Shutdown 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by