how can i perform operations on the basis of image location?

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VIJENDRA 2014-6-12

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https://ww2.mathworks.cn/matlabcentral/answers/133897-how-can-i-perform-operations-on-the-basis-of-image-location

评论： Image Analyst 2014-6-12

I have 2 vectors containing x and y location of a point of an image. My actual image size is 1024*1024 and i have extracted nearly 660 points. these points having x and y location of my image. how can i create a new image in which, value 0 occurs at extracted points and 1 at other locations.

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Answer 1

Image Analyst 2014-6-12

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https://ww2.mathworks.cn/matlabcentral/answers/133897-how-can-i-perform-operations-on-the-basis-of-image-location#answer_140582

在 MATLAB Online 中打开

outputImage = zeros(size(grayImage)); % Initialize image to 0.
for k = 1 : length(x);
  outputImage(y(k), x(k)) = 1;
end

Use false instead of zeros if you want a binary (logical) image instead of a double.

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VIJENDRA 2014-6-12

It works. Thank you so much.

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Answer 2

imene mannou 2014-6-12

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https://ww2.mathworks.cn/matlabcentral/answers/133897-how-can-i-perform-operations-on-the-basis-of-image-location#answer_140559

编辑：Image Analyst 2014-6-12

在 MATLAB Online 中打开

result=I;
result(:,:)=1;
for i=1:length(x)
    result(x(i),y(i))=0;
end

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VIJENDRA 2014-6-12

编辑：VIJENDRA 2014-6-12

I have 2 vectors of size 660 i.e. I have row and column information of the points. 1st vector is containing column number and second vector is containing row number. how could i generate a new image from those 2 reference vectors which have 1's at the point locations and 0's elsewere?

Image Analyst 2014-6-12

imene made a common mistake of thinking that array indices are (x,y). They are not, they are (y,x) because the first index is the row, which is the y value.

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