How can i put my output numbers in for loop to an array
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z=('/Users/fatihnurcin/Desktop/Dandnd/dilated')
cd(z)
list = dir('*.bmp');
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure
subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f=right-left;
end
f
end
This is my whole code, it takes a row from a binary photo and tries to find where its black and where its not and calculate the black area so i want to ask how can i put my outputs(outputs are numbers calculated due to black arena) in an array, i couldn't do it by adding (n) to left and right,
left(n)=find(e(n)==1);
right(n)=find(e(n)==-1);
f(n)=right(n)-left(n);
I need an urgent help , i need to deliver my project in 2 days :/
1 个评论
Joseph Cheng
2014-6-17
reformatted to be readable.
z=('/Users/fatihnurcin/Desktop/Dandnd/dilated')
cd(z)
list = dir('*.bmp');
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f=right-left;
end
f
end
采纳的回答
Jason Nicholson
2014-6-17
This assumes the bitmaps are all the same size:
myArray = [img{:}];
5 个评论
Jason Nicholson
2014-6-18
Honestly, it is clear to me you don't really know what you are doing with MATLAB. After this project is done, you need to read up "getting started" documents for MATLAB. The code below is ugly but works. I believe it is what you want as well.
list = dir('*.bmp');
% preallocate cell array
img = cell(length(list),1);
f = cell(length(list), 250-100);
for i = 1:length(list)
img{i} = imread(list(i).name);
end
for i = 1:length(list)
a=img{i};
b=im2bw(a,0.20);
figure;
subplot(1,3,1);
imshow(b)
c=b(120,100:250);
subplot(1,3,3);
plot(c);
for n=1:length(c);
d= padarray(c,[0 1],'replicate','post');
e(n)=d(n)-d(n+1);
left=find(e==1);
right=find(e==-1);
f{i, n} = right-left;
end
end
更多回答(2 个)
Shravankumar P
2014-6-18
I guess you may go for index mapping. I just give you Idea try this once
for m=1:4
for n=1:4
X(m,n)=x(4*(m-1)+n);
end
end
x is the input which of your interest to put into an array X
0 个评论
ubaid haroon
2017-3-1
what would you do if during the loop, those arrays are different lengths?
0 个评论
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