How to assign parts of one structure to another efficiently?

Question

Joshua 2014-6-19

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编辑： Joshua 2014-6-20

I have a structure, 'D', which contains 'name'. I would like to assign certain parts of this struct to another struct in an efficient manner. What I have now (which works) is the following:

j = 0;
for i = 1:length(D)
  if ( m_u(i) ~= 0 )
      j = j + 1;
      temp(j).name = D(i).name;
  end
end

In this code, the contents of 'D.name' are assigned to 'temp.name' if a vector component is not zero. Is there a more efficient way to do this?

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Answer 1

Sean de Wolski 2014-6-19

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% Sample struct
x = struct('name',cellstr(('A':'I').'))
% sample index (your mu_i)
idx = rand(9,1)>0.5
% extract
[y(1:nnz(idx)).name] = deal(x(idx).name)

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Joshua 2014-6-20

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Thank you very much, Sean. My code ends up being:

[temp(1:nnz(m_u)).name] = deal(D(m_u~=0).name);

This is an order of magnitude faster than the way I was doing this (~0.5 seconds to ~0.07 seconds!).

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