if true
function test(data,t)
figure;
fprintf(1,'%s %d\n', t, length(data));
plot((data(2:end,2)-data(1:end-1,2))./1000000000,data(:,3),'r-');
hold on;
plot((data(2:end,2)-data(1:end-1,2))./1000000000,data(:,4),'g-');
plot((data(2:end,2)-data(1:end-1,2))./1000000000,data(:,5),'b-');
title(t);
dt = (data(2:end, 2)- data(1:end-1, 2))./1000000000;
figure;
hist (dt, [0:0.002:0.5]);
title(t);
end
hi all, i try to subtract the values as shown above so that i can get the time in seconds(the 2nd column in the data contains timestamps in nanoseconds) as shown below:
1 144274932861 -0.16280572 9.49301 -0.36391866
2 144279571533 0.10295067 9.557653 -0.46926352
3 144284942626 0.2908955 9.586384 -0.5650316
4 144289581298 0.2837129 9.657013 -0.51595044
5 144294952392 0.09816227 9.685743 -0.46088383
6 144299591064 -0.09696517 9.736021 -0.33638534
7 144304962158 -0.19871874 9.750386 -0.32680854
8 144309631347 -0.12090719 9.783905 -0.40940848
9 144314971923 0.075417355 9.828198 -0.47524905
10 144319610595 0.14963761 9.831789 -0.46447513 etc
so at the end of the day i want to get the timestamp(2nd column) in secs.
However, the error message that i get is: Matrix dimensions must agree.
Error in test (line 5) plot(data(2:end,2)-data(1:end,2),data(:,3),'r-');
any idea? thanks!
