how to make a vector of 30 rows 1 column with increasing values of elements

2014 6 23
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更新时间：2014 6 26
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I want to make a matrix of 30 rows 1 column like [1;1;1;1;1;2;2;2;2;2;3;3;3;3;3;4;4;4;4;4;5;5;5;5;5;6;6;6;6;6] please anyone help.

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Star Strider
Star Strider 2014-6-23
编辑：Star Strider 2014-6-23

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This works:
V1 = 1:6;
M = repmat(V1', 1, 5)';
V2 = M(:) % Output Vector

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Star Strider
Star Strider 2014-6-23
It does now. I renamed V to V1 after I wrote it, but forgot to update the reference to V1 in the repmat call when I copied it to post it.
Zishan
Zishan 2014-6-23
Dear if i want to make vector of 12 rows and 1 column suppose this vector [1;1;1;1;2;2;2;2;2;2;3;3] please tell me code for this.
Zishan
Zishan 2014-6-23
please tell me a general code I have to make a larger matrix of almost 3 thousand rows.
Star Strider
Star Strider 2014-6-26
I do not see a pattern in:
[1;1;1;1;2;2;2;2;2;2;3;3]
so I do not know what to suggest as to how to generate it. If it is random in the length of each value, use the randi function to determine the number of each integer:
Vlen = 10;
V1 = 1:Vlen;
V2 = [];
for k1 = 1:Vlen
V2 = [V2; k1; repmat(k1, randi(9), 1)];
end
Change Vlen to create the approximate length of the vector you want. If you overshoot, simply truncate it to the length you need.

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