rectangularPulse: no drop to 1/2 at edges

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T
T 2014-6-27
编辑： Matthew Suttinger 2018-3-30
Hello I want to do the fourier of a rectangular pulse which is also 1 at the edges, so that the fourier returns a sinc function. rectangularPulse drops to 1/2 at the edges and does not seem to return the equivalent function if I plot the result vs. a sinc function. I tried ceil but this is not accepted with the fourier function.
Thanks a lot!

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回答（2 个）

Image Analyst
Image Analyst 2014-6-27
So just create it manually
myPulse = [0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ];
  2 个评论
Image Analyst
Image Analyst 2014-6-27
编辑：Image Analyst 2014-6-27
T's "Answer" moved here since it's not an answer to the original question.
I can't, the width of the rectangular pulse depends on a syms variable :/ And besides that, I dont think fourier(myPulse,f,y) would work then anymore anyway.
Image Analyst
Image Analyst 2014-6-27
Make it depend on the variable:
signalLength = 512; % whatever.
myPulse = zeros(1, signalLength);
startingIndex = 20; % Whatever
pulseWidth = 64; % Whatever, e.g. your syms variable value.
myPulse(startingIndex:(startingIndex + pulseWidth - 1)) = 1;

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Matthew Suttinger
Matthew Suttinger 2018-3-30
编辑：Matthew Suttinger 2018-3-30
If you don't mind converting it to a double after applying inputs, wrap the result in the ceil() function.
y = ceil(rectangularPulse(x_start,x_end,x_values));
class(y) % ans = 'double'

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